Quant Quiz

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1. A dealer sells an item for Rs. 667, and makes a profit of 16%. He sells another item of a loss of 10% and in whole process he makes no profit no loss. What was the cost of second item ?
1) Rs. 900 
2) Rs. 920 
3) Rs. 950 
4) Rs. 980 
5) None of these


2. A mixture contains milk and water in the ratio of 4 : 3 on adding 5 litre of water the ratio of milk and water becomes 9 : 8. Find the quantity of water in the mixture ?
1) 9 litre 
2) 15 litre 
3) 21 litre 
4) 24 litre 
5) 27 litre

3. In how many ways can a party of 6 men and 6 women be seated at a round table, so that no two women are adjacent ?
1) 518400 
2) 86400 
3) 14400 
4) 1440 
5) 840

4. In a simultaneous throw of 2 dice, find the probability of getting a total of 9 ?
1) 1/6 
2) 1/36 
3) 25/36 
4) 9/36 
5) 1/9

5. 8 men can complete a piece of work in 15 days and 7 women can complete the same piece of work in 25 days. If all the 8 men and 7 women work together, in how many days will the work get completed ?
1) 7 3/5 days 
2) 6 2/3 days
3) 9 3/8 days
4) 9 2/3 days
5) 9 days

Direction (Q. 6-10): Study the following pie-charts carefully to answer the questions that follow: 

6.What is the total number of girls from state B and C together?
1) 3400 
2) 3460 
3) 4000 
4) 4540 
5) 3450

7. Girls from state D is what percent of Boys of State A?
1) 135% 
2) 66.6% 
3) 73.63% 
4) 80% 
5) 60%

8. Boys from state B is what percent more than girls from state A?
1) 65% 
2) 216.6% 
3) 130.5% 
4) 110.5% 
5) 120%

9. What is the total number of students from state D and E together?
1) 10000 
2) 11000 
3) 12000 
4) 15000 
5) 9000

10. What is the average of total students from 'C' and boys from E?
1) 7000 
2) 4000 
3) 2000 
4) 3500 
5) 3000


Answers:

1. 2

Cost of first item = (667 * 100)/116 = 575

Proit = 667 - 575 = 2

Let the cost of second item is ‘x’

x/10 = 92
x = 920

2. 5

Let the quantity of milk and water are 4x and 3x respectively

4x/(3x + 5) = 9/8 
32x = 27x + 45
x = 45/5 = 9

Quantity of water = 3x = 27 litres.

3. 2
First the six men can sit on round table in (6 - 1)! =
5!ways

Now for no two women adjacent, there are six vacant
seat between each pair of men.
So number of ways 6 women can sit on these six vacant
seat is 6P6 = 6! ways
So total number of arrangements
= 5! ×6! = 120×720 = 86400

4. 5

n(S) = 6×6 = 36
n (E) = 4 ---> {(3,6)(4,5)(5,4)(6,3)}
P(E) = 4/36 = 1/9

5. 3

Req number of days = (15 * 25)/40 = 75/8 = 9 3/8 days

6. 2

7. 3

8. 2

9. 3

10. 4


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